Translation for "keskimeridiaani" to english

Keskimeridiaani

• central meridian

Translation examples

central meridian

Tämän kaistan keskimeridiaani on 27 astetta, joka on sama kuin peruskoordinaatiston kolmas kaista.
The central meridian of this band is 27 degrees, which is the same as the third band of the basic co-ordinate system.

Tällöin paikkakunta, jonka leveysaste on φ ja pituusaste λ, tulee Eckertin IV projektiossa pisteeseen, jonka karteesiset koordinaatit ovat x = 2 4 π + π 2 R ( λ − λ 0 ) ( 1 + c o s θ ) ≈ 0.4222382 R ( λ − λ 0 ) ( 1 + c o s θ ) {\displaystyle x={\frac {2}{\sqrt {4\pi +\pi ^{2}}}}R(\lambda -\lambda _{0})(1+cos\theta )\approx 0.4222382R(\lambda -\lambda _{0})(1+cos\theta )} y = 2 4 π + p i 2 R s i n θ ≈ 1 , 3265004 R s i n θ {\displaystyle y=2{\sqrt {4\pi +pi^{2}}}Rsin\theta \approx 1,3265004Rsin\theta } missä λ0 on kartan keskimeridiaani ja θ on ratkaistava yhtälöstä θ + s i n θ c o s θ + 2 s i n θ = ( 2 + π 2 ) s i n ϕ {\displaystyle \theta +sin\theta cos\theta +2sin\theta =(2+{\frac {\pi }{2}})sin\phi } Tästä yhtälöstä θ {\displaystyle \theta } :lle voidaan lasketa likiarvoja esimerkiksi Newtonin menetelmällä.
Given a radius of sphere R, central meridian λ0 and a point with geographical latitude φ and longitude λ, plane coordinates x and y can be computed using the following formulas: x = 2 4 π + π 2 R ( λ − λ 0 ) ( 1 + cos ⁡ θ ) ≈ 0.422 2382 R ( λ − λ 0 ) ( 1 + cos ⁡ θ ) , y = 2 π 4 + π R sin ⁡ θ ≈ 1.326 5004 R sin ⁡ θ , {\displaystyle {\begin{aligned}x&={\frac {2}{\sqrt {4\pi +\pi ^{2}}}}R\,(\lambda -\lambda _{0})(1+\cos \theta )\approx 0.422\,2382\,R\,(\lambda -\lambda _{0})(1+\cos \theta ),\\y&=2{\sqrt {\frac {\pi }{4+\pi }}}R\sin \theta \approx 1.326\,5004\,R\sin \theta ,\end{aligned}}} where θ + sin ⁡ θ cos ⁡ θ + 2 sin ⁡ θ = ( 2 + π 2 ) sin ⁡ φ . {\displaystyle \theta +\sin \theta \cos \theta +2\sin \theta =\left(2+{\frac {\pi }{2}}\right)\sin \varphi .} θ can be solved for numerically using Newton's method. θ = arcsin ⁡ ≈ arcsin ⁡ φ = arcsin ⁡ λ = λ 0 + x 4 π + π 2 2 R ( 1 + cos ⁡ θ ) ≈ λ 0 + x 0.422 2382 R ( 1 + cos ⁡ θ ) {\displaystyle {\begin{aligned}\theta &=\arcsin \left\approx \arcsin \left\\\varphi &=\arcsin \left\\\lambda &=\lambda _{0}+x{\frac {\sqrt {4\pi +\pi ^{2}}}{2R(1+\cos \theta )}}\approx \lambda _{0}+{\frac {x}{0.422\,2382\,R\,(1+\cos \theta )}}\end{aligned}}} List of map projections Eckert II projection Eckert VI projection Max Eckert-Greifendorff Snyder, John P.; Voxland, Philip M. (1989).